If R is the universal gas constant then the amount of heat needed to raise the temperature of 3 moles of an ideal monoatomic gas from 273 K to 393 K when no work is done is

Step-by-step solution

Since no work is done, the process is isochoric and the heat supplied is used entirely to increase the internal energy of the gas. Q = U = n C_v T For a monoatomic ideal gas, C_v = 3 2 R . Given n = 3 moles, T₁ = 273 K, and T₂ = 393 K. T = 393 - 273 = 120 K Substituting the values: Q = 3 3 2 R 120 Q = 9 2 R 120 = 540 R Answer: 540 R