For a cyclic thermodynamic process

For a cyclic thermodynamic process, the initial and final states of the system are the same.

Since internal energy $U$ is a state function, the change in internal energy over a complete cycle is zero, so $\Delta U = 0$.

According to the first law of thermodynamics, $Q = \Delta U + W$.

Substituting $\Delta U = 0$, we get $Q = W$.

Therefore, for a cyclic process, $Q = W$ and $\Delta U = 0$.

Answer: $Q = W$ and $\Delta U = 0$