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MHT CET 202621 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
21 April
Shift
Morning Shift
Subject
Physics
Chapter
Thermodynamics

MHT CET 2026 · 21 April · Morning Shift · Physics · Thermodynamics

For an adiabatic process, choose the correct relation

For an adiabatic process, choose the correct relation

Options

  1. APTγ=constantPT^\gamma = \text{constant}
  2. BP1−γTγ=constantP^{1-\gamma} T^\gamma = \text{constant}
  3. CPγTγ=constantP^\gamma T^\gamma = \text{constant}
  4. DPγT1−γ=constantP^\gamma T^{1-\gamma} = \text{constant}

Correct answer

B. P1−γTγ=constantP^{1-\gamma} T^\gamma = \text{constant}

Step-by-step solution

For an adiabatic process, the relation between pressure and volume is given by:

PVγ=constantPV^{\gamma} = \text{constant}

From the ideal gas equation, we have PV=nRTPV = nRT, which gives V=nRTPV = \dfrac{nRT}{P}.

Substituting the value of VV in the adiabatic equation, we get:

P(nRTP)γ=constantP \left(\dfrac{nRT}{P}\right)^{\gamma} = \text{constant}

Since nRnR is a constant, this simplifies to:

P1−γTγ=constantP^{1-\gamma} T^{\gamma} = \text{constant}

Answer: P1−γTγ=constantP^{1-\gamma} T^\gamma = \text{constant}
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