MHT CET Medical202622 April 2026Morning ShiftPhysicsWaves and SoundActual
Three tuning forks A, B and C have respective frequencies n₁ , n₂ and n₃ related as n₁ = 1.04 , n₂ and n₃ = 0.99 , n₂ . When A and C are sounded together 5 beats are heard per second. The frequencies of fork A, B and C are respectively.
Options
- A99 Hz, 100 Hz, 104 Hz
- B104 Hz, 99 Hz, 100 Hz
- C100 Hz, 104 Hz, 99 Hz
- D104 Hz, 100 Hz, 99 Hz
Correct answer
D. 104 Hz, 100 Hz, 99 Hz
Step-by-step solution
Given n₁ = 1.04 n₂ and n₃ = 0.99 n₂ . The beat frequency between A and C is given by |n₁ - n₃| = 5 . Substituting the given relations: |1.04 n₂ - 0.99 n₂| = 5 0.05 n₂ = 5 n₂ = 5 0.05 = 100 Hz Calculating n₁ and n₃ : n₁ = 1.04 100 = 104 Hz n₃ = 0.99 100 = 99 Hz The frequencies of forks A, B, and C are 104 Hz , 100 Hz , and 99 Hz respectively. Answer: 104 Hz, 100 Hz, 99 Hz