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MHT CET 202622 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
22 April
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

MHT CET 2026 · 22 April · Morning Shift · Physics · Waves and Sound

Three tuning forks A, B and C have respective frequencies n_1 , n_2...

Three tuning forks A, B and C have respective frequencies n1n_1, n2n_2 and n3n_3 related as n1=1.04 n2n_1 = 1.04\, n_2 and n3=0.99 n2n_3 = 0.99\, n_2. When A and C are sounded together 5 beats are heard per second. The frequencies of fork A, B and C are respectively.

Options

  1. A99 Hz, 100 Hz, 104 Hz
  2. B104 Hz, 99 Hz, 100 Hz
  3. C100 Hz, 104 Hz, 99 Hz
  4. D104 Hz, 100 Hz, 99 Hz

Correct answer

D. 104 Hz, 100 Hz, 99 Hz

Step-by-step solution

Given n1=1.04n2n_1 = 1.04 n_2 and n3=0.99n2n_3 = 0.99 n_2.

The beat frequency between A and C is given by ∣n1−n3∣=5|n_1 - n_3| = 5.

Substituting the given relations:

∣1.04n2−0.99n2∣=5|1.04 n_2 - 0.99 n_2| = 5

0.05n2=50.05 n_2 = 5

n2=50.05=100 Hzn_2 = \dfrac{5}{0.05} = 100 \text{ Hz}

Calculating n1n_1 and n3n_3:

n1=1.04×100=104 Hzn_1 = 1.04 \times 100 = 104 \text{ Hz}

n3=0.99×100=99 Hzn_3 = 0.99 \times 100 = 99 \text{ Hz}

The frequencies of forks A, B, and C are 104 Hz104 \text{ Hz}, 100 Hz100 \text{ Hz}, and 99 Hz99 \text{ Hz} respectively.

Answer: 104 Hz, 100 Hz, 99 Hz
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