NDA2023MathematicsApplication of DerivativesActual
A function is defined by f(x)= | array ccc x+1 & 2 & 3 2 & x+4 & 6 3 & 6 & x+9 array | The function attains local minimum value at:
Options
- Ax=- 28 3
- Bx=-1
- Cx=0
- Dx= 28 3
Correct answer
C. x=0
Step-by-step solution
For local minima f^ (x)=0 3 x^2+28 x=0 x= -28 3 , 0 Now, f^ (x)=6 x+28 Now, f^ (0)=28 0 & f^ ( -28 3 ) 0 So, f ( x ) has local minimum value at x =0