NDA2021MathematicsComplex NumberActual
The smallest positive integer n for which ( 1-i 1+i )^ n^2 where i= -1 , is
Options
- A2
- B4
- C6
- D8
Correct answer
A. 2
Step-by-step solution
aligned & ( 1-i 1+i )^ n^2 =1 & ( (1-i)(1-i) (1+i)(1-i) )^ n^2 =1 aligned aligned & ( (1)^2+(i)^2-2 i 1-(i)^2 )^ n^2 =1 & ( -2 i 2 )^ n^2 =1 (-i)^ n^2 =1 aligned For n=2,(-i)^ 2^2 =(-i)^4=1 Hence, n=2 .