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If matrix A= [ array cc 1-i & i -i & 1-i array ] where i= -1 , then which one of the following is correct?

Options

  1. AA is hermitian
  2. BA is skew-hermitian
  3. C( A )^T+A is hermitian
  4. D( A )^T+A is skew-hermitian

Correct answer

C. ( A )^T+A is hermitian

Step-by-step solution

A square M matrix is said to be Hermitian (or selfadjoint) if it is equal to its. Own Hermitian conjugate, i.e. ( M )^T=M Given Matrix A= [ array cc 1-i & i -i & 1-i array ]( A )^T= [ array cc 1+i & i -i & 1+i array ] aligned & Now, A+( A )^T= [ array cc 1-i & i -i & 1-i array ]+ [ array cc 1+i & i -i & 1+i array ] & = [ array cc 2 & 2 i -2 i & 2 array ]=2 [ array cc 1 & i -i & 1 array ] aligned Conjugate transpose of (A+( A )^T )=2 [ array cc 1 & i -i & 1 array ] Hence, (A+( A )^T ) is hermitian.

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