NDA 2018
Exam NDA
Year 2018
Subject Mathematics
Chapter Matrices
NDA 2018 · Mathematics · Matrices
If A is a 2 × 3 matrix and A B is a 2 × 5 matrix, then B must be a
If
A A A is a
2 × 3 2 \times 3 2 × 3 matrix and
A B A B A B is a
2 × 5 2 \times 5 2 × 5 matrix, then
B B B must be a
Options A 3 × 5 matrix B 5 × 3 matrix C 3 × 2 matrix D 5 × 2 matrix
Correct answer A. 3 × 5 matrix
Step-by-step solution
A is
2 × 3 2 \times 3 2 × 3 matrix
AB is
2 × 5 2 \times 5 2 × 5 matrix
Let 'B' be m
× \times × n matrix
[ A ] 2 × 3 [ B ] m × n = [ A B ] 2 × 5 [\mathrm{A}]_{2 \times 3}[\mathrm{ B}]_{\mathrm{m} \times \mathrm{n}}=[\mathrm{AB}]_{2 \times 5} [ A ] 2 × 3 [ B ] m × n = [ AB ] 2 × 5
number of columns of
A = A= A = number of rows of
B B B .
∴ m = 3 \therefore \mathrm{m}=3 ∴ m = 3
we can observe that
n = 5 \mathrm{n}=5 n = 5 from the product.
So,
B B B is
3 × 5 3 \times 5 3 × 5 matrix.
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