The probability that a family owns a laptop is 0.68 ; that it also owns a desktop is 0.56 . If the probability that it owns both is 0.48 , then what is the probability that a randomly selected family owns a laptop or a desktop?

Step-by-step solution

Let L be the event that a family owns a laptop and D be the event that a family owns a desktop. Given: P(L) = 0.68 P(D) = 0.56 P(L D) = 0.48 The probability that a randomly selected family owns a laptop or a desktop is given by P(L D) . Using the addition theorem of probability: P(L D) = P(L) + P(D) - P(L D) Substituting the given values: P(L D) = 0.68 + 0.56 - 0.48 P(L D) = 1.24 - 0.48 = 0.76