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Passage: Let A , B , C and D be mutually exclusive and exhaustive events and P(A) 2 = P(B) 3 = P(C) 5 = P(D) 8 . Question: What is P(A)+P(B)+P(C) equal to ?

Options

  1. A5 9
  2. B1 18
  3. C2 21
  4. D7 13

Correct answer

A. 5 9

Step-by-step solution

Let P(A) 2 = P(B) 3 = P(C) 5 = P(D) 8 = k P(A) = 2k , P(B) = 3k , P(C) = 5k , P(D) = 8k Since A , B , C and D are mutually exclusive and exhaustive events, P(A) + P(B) + P(C) + P(D) = 1 2k + 3k + 5k + 8k = 1 18k = 1 k = 1 18 P(A) + P(B) + P(C) = 2k + 3k + 5k = 10k 10k = 10 1 18 = 5 9 Answer: 5 9

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