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NDA 2025
Exam
NDA
Year
2025
Subject
Mathematics
Chapter
Probability

NDA 2025 · Mathematics · Probability

Let X be a random variable following binomial distribution whose...

Let XX be a random variable following binomial distribution whose mean and variance are 200 and 160 respectively. What is the value of the number of trials (n)(n)?

Options

  1. A500500
  2. B10001000
  3. C15001500
  4. D20002000

Correct answer

B. 10001000

Step-by-step solution

Let nn be the number of trials, pp be the probability of success, and qq be the probability of failure.

Given mean =np=200= np = 200

Given variance =npq=160= npq = 160

Dividing variance by mean:

npqnp=160200\dfrac{npq}{np} = \dfrac{160}{200}

q=45q = \dfrac{4}{5}

Since p+q=1p + q = 1, we have p=1−45=15p = 1 - \dfrac{4}{5} = \dfrac{1}{5}

Substituting the value of pp in the mean equation:

n×15=200n \times \dfrac{1}{5} = 200

n=1000n = 1000
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