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A, B. C and D are mutually exclusive and exhaustive events. If 2 P ( A )=3 P (B)=4 P ( C )=5 P ( D ) , then what is 77 P ( A ) equal to?

Options

  1. A12
  2. B15
  3. C20
  4. D30

Correct answer

D. 30

Step-by-step solution

aligned & Let 2 P(A)=3 P(B)=4 P(C)=5 P(D)=k & Now P(A)+P(B)+P(C)+P(D)=1 & k 2 + k 3 + k 4 + k 5 =1 & 30 k +20 k +15 k +12 k 60 =1 & 77 k =60 k = 60 77 & P(A)= k 2 = 30 77 & 77 P ( A )=30 aligned

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