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Three fair dice are tossed once. What is the probability that they show different numbers that are in A P ?

Options

  1. A1 12
  2. B1 18
  3. C1 36
  4. D1 72

Correct answer

B. 1 18

Step-by-step solution

n(s)=6 6 6 Different numbers that are in AP. aligned & (1,2,3),(2,3,4),(3,4,5),(4,5,6),(1,3,5),(2,4, & 6),(3,2,1),(4,3,2),(5,4,3),(6,5,4),(5,3,1),(6, & 4,2) & n(E)=12 & P(E)= 12 6 6 6 = 1 18 aligned

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