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NDA 2022
Exam
NDA
Year
2022
Subject
Mathematics
Chapter
Probability

NDA 2022 · Mathematics · Probability

If P(A)=0.5, P(B)=0.7 and P(A B)=0 · 3 , then what is the value of...

If P(A)=0.5, P(B)=0.7 and P(A∩B)=0⋅3P(A \cap B)=0 \cdot 3, then what is the value of P(A′∩B′)+P(A′∩B)+P(A∩B′)?P \left(A^{\prime} \cap B^{\prime}\right)+P\left(A^{\prime} \cap B\right)+P\left(A \cap B^{\prime}\right) ?

Options

  1. A0.60.6
  2. B0.70.7
  3. C0.80.8
  4. D0.90.9

Correct answer

B. 0.70.7

Step-by-step solution

P(A∪B)=P(A)+P(B)−P(A∩B)=0.5+0.7−0.3=0.9∴P(A′∩B′)+P(A∩B)+P(A∩B′)=1−P(A∪B)+P(B)−P(A∩B)+P(A)−P(A∩B)=1−P(A∩B)=1−0.3=0.7\begin{aligned} & P(A \cup B)=P(A)+P(B)-P(A \cap B) \\ & =0.5+0.7-0.3=0.9 \\ & \therefore \quad P\left(A^{\prime} \cap B^{\prime}\right)+P(A \cap B)+P\left(A \cap B^{\prime}\right) \\ & =1-P(A \cup B)+P(B)-P(A \cap B)+P(A)-P(A \cap B) \\ & =1-P(A \cap B)=1-0.3=0.7\end{aligned}
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