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Three fair dice are thrown. What is the probability of getting a total greater than or equal to 15 ?

Options

  1. A19 216
  2. B1 12
  3. C17 216
  4. D5 54

Correct answer

D. 5 54

Step-by-step solution

n(s)=6 6 6=216 Sum greater than or equal to 15 i.e. 15,16,17,18 are (4,5,6) 6 ways; (5,5,6) 3 ways; (5,5,5) 1 way; (6,6,3) 3 ways (6,6,4) 3 ways; (6,6,5) 3 ways; (6,6,6) 1 way n(E)=20P(E)= 20 216 = 5 54

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