A pair of fair dice is rolled. What is the probability that the...

Possibilities of having higher number on second dice First dice Second dice $12,3,4,5,6 \rightarrow 5$ possibilities $23,4,5,6 \rightarrow 4$ possibilities $3 \quad 4,5,6 \rightarrow 3$ possibilities $4 \quad 5,6 \rightarrow 2$ possibilities $5 \quad 6 \rightarrow 1$ possibility Total number of possibilities $=15$ Total number of events $=36\therefore$ Probability $=\frac{15}{36}=\frac{5}{12}$