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A coin is tossed twice. If E and F denote occurrence of head on first toss and second toss respectively, then what is P(E F) equal to?

Options

  1. A1 4
  2. B1 2
  3. C3 4
  4. D1 3

Correct answer

C. 3 4

Step-by-step solution

aligned & P(E)= 1 2 , P(F)= 1 2 & P(E F)=P(E)+P(F)-P(E F) aligned As E & F are two independent event aligned & P(E F)=P(E) P(F) & P(E F)= 1 2 + 1 2 - 1 2 1 2 = 3 4 aligned

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