In eight throws of a die, 5 or 6 is considered a success. The mean...

5 or 6 is success $$\begin{aligned} & \therefore p=\frac{2}{6}=\frac{1}{3} \\ & \therefore q=1-\frac{1}{3}=\frac{2}{3} \\ & \mathrm{n}=8\end{aligned}$$\therefore$Mean$=\mathrm{np}=8$\left(\frac{1}{3}\right)=\frac{8}{3}$ Standard deviation $=\sqrt{n p q}=\sqrt{8\left(\frac{1}{3}\right)\left(\frac{2}{3}\right)}=\sqrt{\frac{16}{9}}=\frac{4}{3}