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NDA2023MathematicsQuadratic EquationActual

A quadratic equation is given by (a+b) x^2-(a+b+c) x+k=0 , where a, b, c are real. If k= c 2 ,(c 0) , then the roots of the equation are:

Options

  1. AReal and equal
  2. BReal and unequal
  3. CReal iff a > c
  4. DComplex but not real

Correct answer

B. Real and unequal

Step-by-step solution

If k = c 2 ,( c 0) then, the given equation is (a+b) x^2-(a+b+c) x+ c 2 =0 Now, D = -( a + b + c ) ^2-4( a + b ) c 2 aligned & a^2+b^2+c^2+2 a b+2 b c+2 c a-2 a c-2 b c & (a+b)^2+c^2 0 ( since, c 0) aligned So, roots are real and unequal.

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