NDA2023MathematicsQuadratic EquationActual
A quadratic equation is given by (a+b) x^2-(a+b+c) x+k=0 , where a, b, c are real. If k= c 2 ,(c 0) , then the roots of the equation are:
Options
- AReal and equal
- BReal and unequal
- CReal iff a > c
- DComplex but not real
Correct answer
B. Real and unequal
Step-by-step solution
If k = c 2 ,( c 0) then, the given equation is (a+b) x^2-(a+b+c) x+ c 2 =0 Now, D = -( a + b + c ) ^2-4( a + b ) c 2 aligned & a^2+b^2+c^2+2 a b+2 b c+2 c a-2 a c-2 b c & (a+b)^2+c^2 0 ( since, c 0) aligned So, roots are real and unequal.