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For how many integral values of k , the equation x^2-4 x+k=0 , where k is an integer, has real roots and both of them lie in the interval (0,5) ?

Options

  1. A3
  2. B4
  3. C5
  4. D6

Correct answer

B. 4

Step-by-step solution

x^2-4 x+K=0 For real roots, D 0 (-4)^2-4(1)(K) 016-4 K 04-K 0K 4 but Both roots lie in (0,5) . K=1,2,3,4 (integers) Number of integral values =4 .

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