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NDA 2016
Exam
NDA
Year
2016
Subject
Mathematics
Chapter
Quadratic Equation

NDA 2016 · Mathematics · Quadratic Equation

Paragraph: Let α and β be the roots of the equation x^2-(1-2 a^2)...

Paragraph: Let α\alpha and β\beta be the roots of the equation x2−(1−2a2)x+(1−2a2)=0x^2-\left(1-2 a^2\right) x+\left(1-2 a^2\right)=0
Question: Under what condition does the above equation have real roots?

Options

  1. Aa2<12\mathrm{a}^2 < \frac{1}{2}
  2. Ba2>12\mathrm{a}^2 > \frac{1}{2}
  3. Ca2≤12\mathrm{a}^2 \leq \frac{1}{2}
  4. Da2≥12\mathrm{a}^2 \geq \frac{1}{2}

Correct answer

D. a2≥12\mathrm{a}^2 \geq \frac{1}{2}

Step-by-step solution

Using ax2+bx+c=0a=1,b=−a x^2+b x+c=0a=1, b=-\left(1-2 a²\right) \& c= (1−2a2)\left(1-2 a²\right) For roots to be real, b2−4ac≥0\mathrm{b}^2-4 \mathrm{ac} \geq0\begin{aligned} & \Rightarrow \quad\left[-\left(1-2 \mathrm{a}^2\right)\rright]^2-4(1)\left(1-2 \mathrm{a}^2\right) \geq0 \\ & \Rightarrow \quad 4 \mathrm{a}^4+4 \mathrm{a}^2-3 \geq 0 \\ & \Rightarrow \quad\left(2 \mathrm{a}^2-1\right)\left(2 \mathrm{a}^2+3\right) \geq 0 \\ & \Rightarrow \quad a² \geq \frac{1}{2} \text{ or }a^2 \leq-\frac{3}{2}\end{aligned}$$
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