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NDA 2011
Exam
NDA
Year
2011
Subject
Mathematics
Chapter
Quadratic Equation

NDA 2011 · Mathematics · Quadratic Equation

The equation x^2-4 x+29=0 has one root 2+5 i . What is the other...

The equation x2−4x+29=0x^2-4 x+29=0 has one root 2+5i2+5 i. What is the other root? (i=−1)(i=\sqrt{-1})

Options

  1. A22
  2. B55
  3. C2+5i2+5 i
  4. D2−5i2-5 i

Correct answer

D. 2−5i2-5 i

Step-by-step solution

The given equation x2−4x+29=0x^2-4 x+29=0 Here, a=1,b=−4,c=29Sumofa=1, b=-4, c=29Sum ofroots =−ba=\frac{-b}{a}=4LetotherrootLet other root=\betaAccordingtothequestion,According to the question,2+5 i+\beta=4β=4−2−5iβ=2−5i\begin{aligned} & \beta=4-2-5 i \\ & \beta=2-5 i\end{aligned}\therefore \quadOtherrootOther root=2-5 i
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