NDA2011MathematicsQuadratic EquationActual
Let , be the roots of the equation (x-a)(x-b)=c, c 0 . Then the roots of the equation (x- )(x- )+c=0 are
Options
- Aa, c
- Bb, c
- Ca, b
- Da+b, a+c
Correct answer
C. a, b
Step-by-step solution
The given equation (x-a)(x-b)=c can be written as x^2-(a+b) x+(a b-c)=0 ...(i) , are the roots of the equation . array rl + & =a+b & =a b-c array ...(ii) If and are the roots of equation aligned (x- )(x- )+c & =0 x^2-( + ) x+( +c) & =0 + = + & =a+b aligned and . = +c=a b by (i i) Clearly, the roots and are a and b .