NDA2011MathematicsQuadratic EquationActual
If one of the roots of the equation a(b-c) x^2+b(c-a) x+c(a-b)=0 is 1 , what is the second root?
Options
- A- b(c-a) a(b-c)
- Bb(c-a) a(b-c)
- Cc(a-b) a(b-c)
- D- c(a-b) a(b-c)
Correct answer
C. c(a-b) a(b-c)
Step-by-step solution
Let other root is of the equation a(b-c) x^2+b(c-a) x+c(a-b)=0 product of roots = c a 1 = c(a-b) a(b-c) other root ( )= c(a-b) a(b-c) .