The observations 4,1,4,3,6,2,1,3,4,5,1,6 are outputs of 12 dices thrown simultaneously. If m and M are means of lowest 8 observations and highest 4 observations respectively, then what is (2 m+M) equal to?

Step-by-step solution

Observations in ascending order 1,1,1,2,3,3,4,4,4,5,6,6m= mean of 1,1,1,2,3,3,4,4= 1+1+1+2+3+3+4+4 8 = 19 8 M= Mean of highest 4 observations (4,5,6,6)M= 4+5+6+6 4 = 21 4 2 m+M=2 ( 19 8 )+ 21 4 =10 .