The variance of five positive observations is 3.6. If four of the observations are 2,2,4,5 then what is the remaining observation?

Step-by-step solution

Since variance = x_i^2 n -(x)^2 aligned & 3.6= 2^2+2^2+4^2+5^2+ x ^2 n - ( 2+2+4+5+ x n )^2 & 3.6= 4+4+16+25+ x ^2 5 - ( 13+ x 5 )^2 aligned On solving, we get aligned & 2 x^2-13 x-7=0 & x =7 aligned