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NDA 2019
Exam
NDA
Year
2019
Subject
Mathematics
Chapter
Statistics

NDA 2019 · Mathematics · Statistics

If V is the variance and M is the mean of first 15 natural numbers,...

If V is the variance and M is the mean of first 15 natural numbers, then what is V+M2\mathrm{V}+\mathrm{M}^2 equal to?

Options

  1. A1243\frac{124}{3}
  2. B1483\frac{148}{3}
  3. C2483\frac{248}{3}
  4. D1249\frac{124}{9}

Correct answer

C. 2483\frac{248}{3}

Step-by-step solution

For first 15 natural numbers. Mean (M)=15+12=8(M)=\frac{15+1}{2}=8 and V=n2−112=22412=563∴V+M2=563+64=2483V=\frac{n^2-1}{12}=\frac{224}{12}=\frac{56}{3}\therefore \quad V+M^2=\frac{56}{3}+64=\frac{248}{3}
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