NEET2014ChemistryChemical EquilibriumActual
For a given exothermic reaction K p and K ' p are the equilibrium constants at temperatures T 1 and T 2 respectively (T 2 .>T 1 ). Assuming that heat of reaction is constant in temperatures range between T 1 and T 2 , it is readily observed that:
Options
- AK p > K ' p
- BK p < K ' p
- CK p = K ' p
- DK p = 1 K ' p
Correct answer
A. K p > K ' p
Step-by-step solution
log ⁡ K 2 K 1 = ∆ H o 2.303 R 1 T 1 - 1 T 2 T 2 > T 1 So K p >   K ' p (exothermic reaction) (Since T 2 > T 1 )