NEET 2011
- Exam
- NEET
- Year
- 2011
- Subject
- Chemistry
- Chapter
- Chemical Equilibrium
NEET 2011 · Chemistry · Chemical Equilibrium
For the reaction, (N _ 2 ( g)+O _ 2 ( g) leftharpoons 2 NO(g)), the...
For the reaction, (\mathrm{N}}_{2}( \mathrm{ g})+\mathrm{O}}_{2}(\mathrm{ g}) \rightleftharpoons2 \mathrm{NO}(\mathrm{g})), the equilibrium constant is (\mathrm{K}}_{1}). The equilibrium constant is (\mathrm{K}}_{2}) for (2 \mathrm{NO}(\mathrm{g})+\mathrm{O}}_{2}( \mathrm{ g}) \rightleftharpoons2 \mathrm{NO}}_{2}(\mathrm{ g})). What is K for the reaction (\mathrm{NO}}_{2}( \mathrm{ g}) \rightleftharpoons \frac{1}{2} \mathrm{ N}}_{2}( \mathrm{ g})+\mathrm{O}}_{2}(\mathrm{ g})?)
Options
- A(\frac{1}{\left(K_1 K_2\right)})
- B(\frac{1}{\left(2 K_1 K_2\right)})
- C(\frac{1}{\left(4 K_1 K_2\right)})
- D(\left(\frac{1}{K_1 K_2}\right)^{1 / 2})
Correct answer
B. (\frac{1}{\left(2 K_1 K_2\right)})
Step-by-step solution
\begin{aligned}
& \mathrm{N}_2(g)+\mathrm{O}_2(g) \rightleftharpoons 2 \mathrm{NO}(g) ; K_1 \\
& \frac{2 \mathrm{NO}(g)+\mathrm{O}_2(g) \rightleftharpoons 2 \mathrm{NO}_2(g) ; K_2}{\mathrm{~N}_2(g)+2 \mathrm{O}_2(g) \rightleftharpoons 2 \mathrm{NO}_2(g) ; K=K_1 \times K_2} \cdots \\
& \therefore \text{ For } \mathrm{NO}_2(g) \rightleftharpoons \frac{1}{2} \mathrm{~N}_2(g)+\mathrm{O}_2(g) ; \\
& K^{\prime}=\left[\frac{1}{K_1 K_2}\right]^{1 / 2}
\end{aligned}