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NEET2010ChemistryChemical EquilibriumActual

The reaction, (2 ~A _ ( g ) + B _ ( g ) 3 C _ ( g ) + D _ ( g ) ) is begun with the concentrations of (A ) and (B ) both at an initial value of 1.00 M When equilibrium is reached, the concentration of (D ) is measured and found to be 0.25 M. The value for the equilibrium constant for this reaction is given by the expression

Options

  1. A( [(0.75)^3(0.25) ] [(1.00)^2(1.00) ] )
  2. B( [(0.75)^3(0.25) ] [(0.50)^2(0.75) ] )
  3. C( [(0.75)^3(0.25) ] [(0.50)^2(0.25) ] )
  4. D( [(0.75)^3(0.25) ] [(0.75)^2(0.25) ] )

Correct answer

B. ( [(0.75)^3(0.25) ] [(0.50)^2(0.75) ] )

Step-by-step solution

( array lcccc & 2 A_ (g) & + & B_ (g) & & 3 C_ (g) & + & D_ (g) Initial moles : & 1 & & 1 & & 0 & & 0 Moles at eq. : & 1-(2 0.25) & & 1-0.25 & & 3 0.25 & & 0.25 & =0.5 & & =0.75 & & =0.75 & & =0.25 array ) Equilibrium constant, (K= [C]^3[D] [A]^2[B] ) ( K= (0.75)^3(0.25) (0.5)^2(0.75) )

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