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NEET 2024
Exam
NEET
Year
2024
Subject
Chemistry
Chapter
Chemical Equilibrium

NEET 2024 · Chemistry · Chemical Equilibrium

At a given temperature and pressure, the equilibrium constant...

At a given temperature and pressure, the equilibrium constant values for the equilibria are given below: 3 A2+B2⇌2 A3 B, K13 \mathrm{~A}_2+\mathrm{B}_2 \rightleftharpoons 2 \mathrm{~A}_3 \mathrm{~B}, \mathrm{~K}_1 A3 B⇌32 A2+12 B2, K2\mathrm{A}_3 \mathrm{~B} \rightleftharpoons \frac{3}{2} \mathrm{~A}_2+\frac{1}{2} \mathrm{~B}_2, \mathrm{~K}_2 The relation between K1\mathrm{K}_1 and K2\mathrm{K}_2 is :

Options

  1. AK12=2 K2\mathrm{K}_1^2=2 \mathrm{~K}_2
  2. BK2=K12\mathrm{K}_2=\frac{\mathrm{K}_1}{2}
  3. CK1=1K2\mathrm{K}_1=\frac{1}{\sqrt{\mathrm{K}_2}}
  4. DK2=1K1\mathrm{K}_2=\frac{1}{\sqrt{\mathrm{K}_1}}

Correct answer

D. K2=1K1\mathrm{K}_2=\frac{1}{\sqrt{\mathrm{K}_1}}

Step-by-step solution

3 A2+B2⇌2 A3 B;K13 \mathrm{~A}_2+\mathrm{B}_2 \rightleftharpoons 2 \mathrm{~A}_3 \mathrm{~B} ; \mathrm{K}_1 2 A3 B⇌3 A2+B2;K′=1 K12 \mathrm{~A}_3 \mathrm{~B} \rightleftharpoons 3 \mathrm{~A}_2+\mathrm{B}_2 ; \mathrm{K}^{\prime}=\frac{1}{\mathrm{~K}_1} 12A3B⇌32A2+12B2;K2=K′\frac{1}{2} A_3 B \rightleftharpoons \frac{3}{2} A_2+\frac{1}{2} B_2 ; K_2=\sqrt{K^{\prime}} K2=K′\mathrm{K}_2=\sqrt{\mathrm{K}^{\prime}} =1K1=\frac{1}{\sqrt{K_1}}
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