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NEET 2008
Exam
NEET
Year
2008
Subject
Chemistry
Chapter
Chemical Equilibrium

NEET 2008 · Chemistry · Chemical Equilibrium

The value of equilibrium constant of the reaction HI(g)...

The value of equilibrium constant of the reaction \mathrm{HI}(\mathrm{g}) \rightleftharpoons \frac{1}{2} \mathrm{H}}_{2}( \mathrm{~g})+\frac{1}{2} \mathrm{I}}_{2}  is \text{ is }8.0 The equilibrium constant of the reaction H2( g)+\mathrm{H}_2(\mathrm{~g})+\mathrm{I}2( g)⇌2HI(g)_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g}) will be

Options

  1. A18\frac{1}{8}
  2. B116\frac{1}{16}
  3. C164\frac{1}{64}
  4. D16

Correct answer

C. 164\frac{1}{64}

Step-by-step solution

\mathrm{HI} \rightleftharpoons \frac{1}{2} \mathrm{H}_2+\frac{1}{2} $\mathrm{I}$_2, \mathrm{~K}_1=8.0 or 2HI⇌H2+2 \mathrm{HI} \rightleftharpoons \mathrm{H}_2+\mathrm{I}2, K2=64 or H2+_2, \mathrm{~K}_2=64 \text{ or } \mathrm{H}_2+\mathrm{I}2_2 \rightleftharpoons 2 HI\mathrm{HI}, K3=\mathrm{K}_3=164\frac{1}{64}
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