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NEET2007ChemistryChemical EquilibriumActual

The following equilibrium constant are given: aligned N ₂+3 H ₂ & 2 NH ₃ ; K ₁ ~N ₂+ O ₂ & 2 NO ; K ₂ H ₂+1 / 2 O ₂ & H ₂ O ; K ₃ aligned The equilibrium constant for the oxidation of NH ₃ by oxygen to give NO is:

Options

  1. AK ₂ ~K ₃^2 ~K ₁
  2. BK ₂^2 ~K ₃ ~K ₁
  3. CK ₁ ~K ₂ ~K ₃
  4. DK₂ K₃^3 K₁

Correct answer

D. K₂ K₃^3 K₁

Step-by-step solution

Given, aligned & N ₂+3 H ₂ 2 NH ₃ ; K ₁ & ~N ₂+ O ₂ 2 NO ; K ₂ & H ₂+ 1 2 O ₂ H ₂ O ; K ₃ aligned We have to calculate aligned & 4 NH ₃+5 O ₂ 4 NO +6 H ₂ O ; K = ? & or 2 NH ₃+ 5 2 O ₂ 2 NO +3 H ₂ O aligned For this equation K = [ NO ]^2 [ H ₂ O ]^3 [ NH ₃ ]^2 [ O ₂ ]^ 5 / 2 but aligned K ₁ & = [ NH ₃ ]^2 [ ~N ₂ ] [ H ₂ ]^3 ~K ₂ & = [ NO ]^2 [ ~N ₂ ] [ O ₂ ] K ₃ & = [ H ₂ O ] [ H ₂ ] [ O ₂ ]^ 1 / 2 ~K ₃ & = [ H ₂ O ^3 . [ H ₂ ]^3 [ O ₂ ]^ 3 / 2 aligned Now aligned & K ₂ K ₃ ^3 ~K ₁ = [ NO ]^2 [ ~N ₂ ] [ O ₂ ] [ H ₂

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