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NEET 2008

Exam: NEET
Year: 2008
Subject: Chemistry
Chapter: Classification of Elements and Periodicity in Properties

NEET 2008 · Chemistry · Classification of Elements and Periodicity in Properties

The correct order of decreasing second ionisation enthalpy of Ti...

The correct order of decreasing second ionisation enthalpy of Ti (22), V (23), Cr (24)

and \mathrm{Mn}(25)

is

Options

A $\mathrm{Ti}>\mathrm{V}>\mathrm{Cr}>\mathrm{Mn}$
B $\mathrm{Cr}>\mathrm{Mn}>\mathrm{V}>\mathrm{Ti}$
C $\mathrm{V}>\mathrm{Mn}>\mathrm{Cr}>\mathrm{Ti}$
D $\mathrm{Mn}>\mathrm{Cr}>\mathrm{Ti}>\mathrm{V}$

Correct answer

B. $\mathrm{Cr}>\mathrm{Mn}>\mathrm{V}>\mathrm{Ti}$

Step-by-step solution

\mathrm{Cr}(

24)

\rightarrow[\mathrm{Ar}]

3 d⁵ 4 s¹ After removing one electron from chromium, the resulting structure becomes more stable. Hence

\mathrm{Cr}

has higher second ionisation enthalpy. Thus, the correct order is

\mathrm{Cr}

>

\mathrm{Mn}

>

\mathrm{V}

>

\mathrm{Ti}

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