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The molar conductance of NaCl ,   HCl and CH 3 COONa at infinite dilution are 126 . 45 ,   426 . 16 and 91 . 0   Scm 2   mol - 1 respectively. The molar conductance of CH 3 COOH at infinite dilution is. Choose the right option for your answer.

Options

  1. A201 . 28 Scm 2   mol - 1
  2. B390 . 71   S   cm 2   mol - 1
  3. C698 . 28 Scm 2   mol - 1
  4. D540 . 48 Scm 2   mol - 1

Correct answer

B. 390 . 71   S   cm 2   mol - 1

Step-by-step solution

Λ m ∞ CH 3 COOH = Λ m ∞ CH 3 COONa + Λ m ∞ ( HCl ) - Λ m ∞ ( NaCl ) = 91 + 426 . 16 - 126 . 45 = 390 . 71   S   cm 2   mol - 1

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