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NEET2018ChemistryElectrochemistryActual

Consider the change in oxidation state of Bromine corresponding to different emf values, as shown in the diagram below: Then, what is the species undergoing disproportionation?

Options

  1. AB r 2
  2. BHBr O
  3. CBr O 4 -
  4. DBr O 3 -

Correct answer

B. HBr O

Step-by-step solution

Calculate E cell o corresponding to each compound undergoing disproportionation reaction. The reaction for which E cell o comes out +ve is spontaneous. HBrO → B r 2               E o = 1.595 ,   S R P   Cathode 2 HBrO → B r 2 + B r O 3 - E c e l l o = SRP (cathode) - SRP (Anode) = 1.595 - 1.5 = 0 .095   V E cell o > 0 ⇒     Δ G o < 0 [spontaneous]

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