Let
s be the solubility of the salt in water.
For
AgBr:
AgBr⇌Ag++Br−Ksp=s2s=5.0×10−13=50×10−14≈7.07×10−7 MFor
Zn(OH)2:
Zn(OH)2⇌Zn2++2OH−Ksp=s(2s)2=4s3s=(41.0×10−15)1/3=(250×10−18)1/3≈6.3×10−6 MFor
Hg2Cl2:
Hg2Cl2⇌Hg22++2Cl−Ksp=s(2s)2=4s3s=(41.3×10−18)1/3=(0.325×10−18)1/3≈6.87×10−7 MComparing the solubilities:
6.3×10−6>7.07×10−7>6.87×10−7Thus, the correct order of solubility is
Zn(OH)2>AgBr>Hg2Cl2.
Answer:
Zn(OH)2>AgBr>Hg2Cl2