NEET2019ChemistryIonic EquilibriumActual
The molar solubility of CaF ₂ ( K _ sp =5.3 10⁻¹¹ ) in 0.1 M solution of NaF will be
Options
- A5.3 10¹¹ ~mol ~L ⁻¹
- B5.3 10⁻⁸ ~mol ~L ⁻¹
- C5.3 10⁻⁹ ~mol ~L ⁻¹
- D5.3 10⁻¹⁰ ~mol ~L ⁻¹
Correct answer
C. 5.3 10⁻⁹ ~mol ~L ⁻¹
Step-by-step solution
Let the solubility of CaF ₂ in 0.1 M NaF is ' S ' mol L ⁻¹