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NEET2019ChemistryIonic EquilibriumActual

pH of a saturated solution of C a O H 2 is 9 . The solubility product K s p of C a O H 2 is:

Options

  1. A0.5 × 10 - 15
  2. B0.25 × 10 - 10
  3. C0.125 × 10 - 15
  4. D0.5 × 10 - 10

Correct answer

A. 0.5 × 10 - 15

Step-by-step solution

C a O H 2 ⇌ C a + 2 S + 2 O H - 2 S p H of saturated solution = 9 p H = 9 , H + = 10 - 9 Hence O H - = 10 - 14 10 - 9 = 10 - 5 2 s = 10 - 5 , s = 10 - 5 2 k s p for C a O H 2 ⇒ 4 s 3 ⇒ 4 × 10 -5 2 3 = 10 -1 5 2 = 0.5 × 10 - 15

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