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NEET 2019
Exam
NEET
Year
2019
Subject
Chemistry
Chapter
Solid State

NEET 2019 · Chemistry · Solid State

A compound is formed by cation C and anion A . The anions form...

A compound is formed by cation CC and anion AA . The anions form hexagonal close packed (hcp) lattice and the cations occupy 7575% of octahedral voids. The formula of the compound is:

Options

  1. AC2A3{C}_{2}{A}_{3}
  2. BC3A2{C}_{3}{A}_{2}
  3. CC3A4{C}_{3}{A}_{4}
  4. DC4A3{C}_{4}{A}_{3}

Correct answer

C. C3A4{C}_{3}{A}_{4}

Step-by-step solution

In HCP lattice, effective number of atoms present in unit cell
=6= 6

Thus, the number of anions per unit cell =6= 6

The number of octahedral voids is equal to the effective number of atoms in the unit cell.

According to the question, cations are occupying 7575 % of the octahedral voids,

Thus, the number of cations per unit cell =6×75100=92= 6 \times \dfrac{75}{100} = \dfrac{9}{2}


The formula of the ionic compound represents the simplest ratio of the ions present in it. The cation is written first and then the anion.

Thus, the formula of the given compound=C92A6⇒C9A12=C3A4= C\dfrac{9}{2}{A}_{6} ⇒ {C}_{9}{A}_{12} = {C}_{3}{A}_{4}

Hexagonal close packed (hcp) refers to layers of spheres packed so that spheres in alternating layers overlie one another.

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