NEET2018ChemistrySolid StateActual
Iron exhibits BCC structure at room temperature. Above 900 ° C , it transforms to FCC structure. The ratio of the density of iron at room temperature to that at 900 ° C is (assuming molar mass and atomic radii of iron remains constant with temperature)
Options
- A3 3 4 2
- B4 3 3 2
- C3 2
- D1 2
Correct answer
A. 3 3 4 2
Step-by-step solution
BCC = 4 r = 3 a ⇒ a = 4 r 3 FCC = 4 r = 2 a ⇒ a = 4 r 2 d BCC d FCC = Z BCC × M N A   a 3 Z FCC × M N A   a 3 = 2 × M N A 4 r 3 3 4 × M N A × 4 r 2 3 = 3 4 3 2   .