The ionic radii of A ^ + and B ^ - ions are 0.98 × 10 ^ - 10 m and 1.81 × 10 ^ - 10 m . The coordination number of each ion in AB is

Correct answer: A. 6 Radius ratio of ( A ^ + B ^ - ) = 0.98 × 10 ^ - 10 m 1.81 × 10 ^ - 10 m = (0.98)/(1.81) = 0.541 If the radius ratio is between 0.414 and 0.732 then Co-ordination number is 6.

NEET 2016

Exam: NEET
Year: 2016
Subject: Chemistry
Chapter: Solid State

NEET 2016 · Chemistry · Solid State

The ionic radii of A ^ + and B ^ - ions are 0.98 × 10 ^ - 10 m and...

The ionic radii of

{A}^{+}

and

{B}^{-}

ions are

0.98 \times {10}^{- 10}m

and

1.81 \times {10}^{- 10}m

. The coordination number of each ion in AB is

Options

Correct answer

A. 6

Step-by-step solution

Radius ratio of

\left(\dfrac{{A}^{+}}{{B}^{-}}\right) = \dfrac{0.98 \times {10}^{- 10}m}{1.81 \times {10}^{- 10}m} = \dfrac{0.98}{1.81} = 0.541

If the radius ratio is between 0.414 and 0.732 then Co-ordination number is 6.

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