Copper crystallizes in an FCC unit cell with cell edge of 3 .608 × 10 − 8   cm . The density of copper is 8 . 92   g / cm 3 , Calculate the atomic mass of copper.

Step-by-step solution

The number of effective atoms in a FCC unit cell, Z = 4   atoms M =   d ×   N 0 ×   a 3    Z Where, M is atomic mass of copper d is density of copper= 8   . 92   g / c m 3 , N 0 is the Avogadro number = 6 .022 ×   10 23   mol - 1 a is the edge length = 3.608 × 10 − 8 cm Substituting the values in the formula, ⇒ M = 8 .92 g / cm 3 × 6 .022 × 10 23 atom / mol × ( 3 .608 × 10 − 8 cm ) 3 4   atoms ⇒