NEET2009ChemistrySolid StateActual
The figure shows elliptical orbit of a planet m about the sun S . The shaded area S C D is twice the shaded area S A B . If t ₁ is the time for the planet to move from C to D and t ₂ is the time to move from A to B , then
Options
- At₁>t₂
- Bt₁=4 t₂
- Ct ₁=2 t ₂
- Dt ₁= t ₂
Correct answer
C. t ₁=2 t ₂
Step-by-step solution
Key Idea Apply Kepler's law of area of planetary motion. The line joining the sun to the planet sweeps out equal areas in equal time interval i e , areal velocity is constant. dA dt = constant or A ₁ t ₁ = A ₂ t ₂ array llrl & t ₁ & = A ₁ ~A ₂ t ₂ Given & A ₁ & =2 ~A ₂ & t ₁ & =2 t ₂ array