NEET2008ChemistrySolid StateActual
Four diatomic species are listed below in different sequences. Which of these presents the correct order of their increasing bond order?
Options
- AO ₂⁻ < NO < C ₂²⁻ < He ₂⁺
- BNO < C ₂²⁻ < O ₂⁻ < He ₂⁺
- CC ₂²⁻ < He ₂⁺ < NO < O ₂⁻
- DHe ₂⁺ < O ₂⁻ < NO < C ₂²⁻
Correct answer
D. He ₂⁺ < O ₂⁻ < NO < C ₂²⁻
Step-by-step solution
aligned & Key Idea : Bond order = N_b-N_a 2 & He ₂⁺:( 1 s)^2 ( ^* 1 s )^1 & Bond order = 2-1 2 = 1 2 & C ₂²⁻: & K K( 2 s)^2( * 2 s)^2 ( 2 p_x )^2 ( 2 p_y )^2 ( 2 p_z )^2 & Bond order = 8-2 2 =3 aligned gathered O ₂⁻: K K( 2 s)^2( 2 s)^2 ( 2 p_z )^2 ( 2 p_x )^2 ( 2 p_y )^2 ( 2 p_x )^2 ( 2 p_y )^1 Bond order = 8-5 2 =1 1 2 gathered aligned & NO : K K( 2 s)^2( 2 s)^2 ( 2 p_z )^2 ( 2 p_x )^2 & . ( 2 p_y )^2( ) p_x )^1 aligned Bond order = 8-3 2 =2 1 2 Hence, the order of increasing bond order is as: ( 1 2 ) He ₂⁺ < (1