CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm . Given that the atomic mass of Cs =133 and that of Br =80 amu and Avogadro number being 6.02 10²³ ~mol ⁻¹ . the density of CsBr is:

Step-by-step solution

Density of CsBr = Z M a^3 N ₀ Z No. of atoms in the bec unit cell =2 M Molar mass of CaBr =133+80=213a Edge length of unit cell =436.6 pm =436.6 10⁻¹⁰ ~cm N ₀ is Avogadro number aligned & Density & = 2 213 (436.6 10⁻¹⁰ )^3 6.02 10²³ & =8.50 ~g / cm ^3 aligned For a unit cell = 8.50 2 =4.25 ~g / cm ^3 Related Theory When particles are closed packed resulting in either cpp or hcp structure, two types of voids are generated are Tetrahedral voids are holes or voids. (Coordination number of a tetrahedral void is 4.) Oct