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NEET 2008
Exam
NEET
Year
2008
Subject
Chemistry
Chapter
Solid State

NEET 2008 · Chemistry · Solid State

If the lattice parameter for a crystalline structure is 3.6 Å ,...

If the lattice parameter for a crystalline structure is 3.6A˚3.6 Å, then the atomic radius in fcc crystal is

Options

  1. A1.81A˚1.81 Å
  2. B2.10A˚2.10 Å
  3. C2.92A˚2.92 Å
  4. D1.27A˚1.27 Å

Correct answer

D. 1.27A˚1.27 Å

Step-by-step solution

Atomic radius is the distance between two nearest neighbours. For fcc crystal Atomic radius =122×=\frac{1}{2 \sqrt{2}} \times lattice parameter or r=a22r=\frac{a}{2 \sqrt{2}} or r=3.622A˚=1.27A˚r=\frac{3.6}{2 \sqrt{2}} Å=1.27 Å
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