NEET2008ChemistrySolid StateActual
If the lattice parameter for a crystalline structure is 3.6 Å , then the atomic radius in fcc crystal is
Options
- A1.81 Å
- B2.10 Å
- C2.92 Å
- D1.27 Å
Correct answer
D. 1.27 Å
Step-by-step solution
Atomic radius is the distance between two nearest neighbours. For fcc crystal Atomic radius = 1 2 2 lattice parameter or r= a 2 2 or r= 3.6 2 2 Å=1.27 Å