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Mass of glucose ( C ₆ H ₁₂ O ₆ ) required to be dissolved to prepare one litre of its solution which is isotonic with 15 ~g ~L ⁻¹ solution of urea ( NH ₃ CONH ₂ ) is (Given: Molar mass in g mol ⁻¹ C : 12, H : 1, O : 16, ~N : 14 )

Options

  1. A55 g
  2. B15 g
  3. C30 g
  4. D45 g

Correct answer

D. 45 g

Step-by-step solution

For isotonic solutions [osmotic pressure must be equal] ₁= ₂ C ₁ RT = C ₂ RT C ₁= C ₂ m 180 1 = 15 60 1 ( ~m is the mass of glucose) m= 180 4 =45 ~g

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