The Henry's law constant (K_H) values of three gases (A, B, C) in water are 145,2 × 10^ -5 and 35 kbar , respectively. The solubility of these gases in water follow the order:

Correct answer: A. B C A Value of Henry's law constant 1 Solubility of gas Higher the value of K_H at a given pressure, lower is the solubility of the gas in the liquid. K_H value of gases (given) : A Order of solubility of gases in water : B

NEET 2024

Exam: NEET
Year: 2024
Subject: Chemistry
Chapter: Solutions

NEET 2024 · Chemistry · Solutions

The Henry's law constant (K_H) values of three gases (A, B, C) in...

The Henry's law constant

\left(\mathrm{K}_H\right)

values of three gases

(\mathrm{A}, \mathrm{B}, \mathrm{C})

in water are

145,2 \times 10^{-5}

and 35 kbar , respectively. The solubility of these gases in water follow the order:

Options

AB $\gt$ C $\gt$ A
BA $\gt$ C $\gt$ B
CA $\gt$ B $\gt$ C
DB $\gt$ A $\gt$ C

Correct answer

A. B $\gt$ C $\gt$ A

Step-by-step solution

Value of Henry's law constant

\propto \frac{1}{\text{ Solubility of gas }}

Higher the value of

\mathrm{K}_H

at a given pressure, lower is the solubility of the gas in the liquid.

\mathrm{K}_H

value of gases (given) :

\mathrm{A}\gt\mathrm{C}\gt\mathrm{B}\therefore \quad

Order of solubility of gases in water :

\mathrm{B}\gt\mathrm{C}\gt\mathrm{A}

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