NEET2021ChemistrySolutionsActual
The following solutions were prepared by dissolving 10   g of glucose C 6 H 12 O 6 in 250   mL of water P 1 , 10   g of urea CH 4 N 2 O in 250   mL of water P 2 and 10   g of sucrose C 12 H 22 O 11 in 250   mL of water P 3 . The right option for the decreasing order of osmotic pressure of these solutions is:
Options
- AP 2 > P 1 > P 3
- BP 1 > P 2 > P 3
- CP 2 > P 3 > P 1
- DP 3 > P 1 > P 2
Correct answer
A. P 2 > P 1 > P 3
Step-by-step solution
Osmotic pressure ( π ) = CRT At same temperature, π ∝ C Solution: ( 1 ) C 1 = 10 180 = 10 180 × 4 C 1 = 250 1000 = 40 180 = 2 9 C 1 = 0 . 222 M Solution: ( 2 ) C 2 = 10 60 250 1000 = 1 6 × 4 = 0 . 667 M Solution: ( 3 ) C 3 = 10 342 × 1000 250 = 0 . 1169 M ∵ C 2 > C 1 > C 3 ∴ Hence, order: P 2 > P 1 > P 3